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| May 13, 2018 01:09PM |
So we have this ...
One half the height of G1 divided into the diagonal of G2 will give us the ratio of the number of days in a year between Mercury and Earth. (365.25 / 88 = 581.31343 / 140 = 4.152
The ratio of 140 / 88 is 1.5909091 and is the reciprocal of 1 / Pi x 2
and also happens to equal ... the ratio between the average orbital speed of Mercury (47.36163 km/sec) and Earth (29.78273 km/sec)
Simple and easy as Pi ...
best
Don Barone
Cherry Picking - If you can't debate your opponents on the substance of the issue, crush them on the minor details.
Edited 1 time(s). Last edit at 05/13/2018 01:11PM by Ahatmose.
One half the height of G1 divided into the diagonal of G2 will give us the ratio of the number of days in a year between Mercury and Earth. (365.25 / 88 = 581.31343 / 140 = 4.152
The ratio of 140 / 88 is 1.5909091 and is the reciprocal of 1 / Pi x 2
and also happens to equal ... the ratio between the average orbital speed of Mercury (47.36163 km/sec) and Earth (29.78273 km/sec)
Simple and easy as Pi ...
best
Don Barone
Cherry Picking - If you can't debate your opponents on the substance of the issue, crush them on the minor details.
Edited 1 time(s). Last edit at 05/13/2018 01:11PM by Ahatmose.
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